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Math Question: How is Acceleration Between These 2 People the Same?

Mr. Friscus

Governor
If Acceleration the change in velocity, and Velocity is displacement/time

Person A drives super slow, going 2 blocks east and 2 blocks north at 5mph in X minutes

Person B drives like a maniac, and goes 20 blocks east at 70mph, 20 blocks north at 80mph, 18 blocks west at 90mph, and 18 blocks south at 100mph in X minutes​

Both end up at the same spot, thus both have the same displacement.

Thus, they'd have the same acceleration over X amount of time?

It doesn't add up on face value.
 
If Acceleration the change in velocity, and Velocity is displacement/time

Person A drives super slow, going 2 blocks east and 2 blocks north at 5mph in X minutes

Person B drives like a maniac, and goes 20 blocks east at 70mph, 20 blocks north at 80mph, 18 blocks west at 90mph, and 18 blocks south at 100mph in X minutes​

Both end up at the same spot, thus both have the same displacement.

Thus, they'd have the same acceleration over X amount of time?

It doesn't add up on face value.

They have the same net motion. It's like a hurricane, whirling at 100 miles an hour but moving as a whole body at 5 miles an hour.

By the way, displacement without motion is impossible. So is the quantum leap unless its motion is in a different dimension.
 

Winston

Do you feel lucky, Punk
If Acceleration the change in velocity, and Velocity is displacement/time

Person A drives super slow, going 2 blocks east and 2 blocks north at 5mph in X minutes

Person B drives like a maniac, and goes 20 blocks east at 70mph, 20 blocks north at 80mph, 18 blocks west at 90mph, and 18 blocks south at 100mph in X minutes​

Both end up at the same spot, thus both have the same displacement.

Thus, they'd have the same acceleration over X amount of time?

It doesn't add up on face value.
What are you calling displacement because I do not see that any mass was displaced.

You do know that the faster vehicle traveled farther changing directions so often that they went no where so to speak. I haven't done the math but it seems right
 
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